简单思路：很简单，记录一个 map，遍历数组，查看 target - cur 是否存在 map 中，再查看两个下标是否一致，就可以得出结果了
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/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = function (nums, target) {
const map = nums.reduce((res, cur, index) => {
res[cur] = index;
return res;
}, {});
for (let index = 0; index < nums.length; index++) {
const cur = nums[index];
const targetMap = map[target - cur];
if (targetMap && targetMap !== index) {
return [index, targetMap];
}
}
};
const nums = [3, 3],
target = 6;
console.log(twoSum(nums, target));
